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  #1801  
Old 16.04.2018, 15:55
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Re: Ask a Scientist

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fill the cup to the brim and weigh it =m1
put the ball in the cup and so let some water out, ensure the ball is completely under water.
get the ball out without losing any more water
weigh the cup again = m2
and calculate the weight of water lost m3 =m1 - m2
weigh the ball alone = m4

Density = m4/m3

now weigh the cup again and calcuate the weight of water lost
That's the messy way, but nowhere near as elegant as the old fashioned way.
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  #1802  
Old 16.04.2018, 15:57
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Re: Ask a Scientist

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That's the messy way, but nowhere near as elegant as the old fashioned way.
You did not write it was a balance scale?
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  #1803  
Old 16.04.2018, 15:58
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Re: Ask a Scientist

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No but Archimedes did
lol...screwed! I think i might be starting to come down with..what's it called again?

thanks for the clarification.
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  #1804  
Old 16.04.2018, 16:00
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Re: Ask a Scientist

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You did not write it was a balance scale?
It can be a balance or a platform scale, or even a suspension scale (like fishermen use, but accurate).
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  #1805  
Old 16.04.2018, 16:18
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Re: Ask a Scientist

Good luck to the rest of you attempting solutions! I think that most of my group would struggle to even remeber enough to understand Jag's question.
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  #1806  
Old 16.04.2018, 18:20
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Re: Ask a Scientist

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lol...screwed! I think i might be starting to come down with..what's it called again?

thanks for the clarification.
It is called "Alice" as in
Quote:
They're changing guard at Buckingham Palace -
Christopher Robin went down with Alice.
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  #1807  
Old 16.04.2018, 19:44
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Re: Ask a Scientist

Not sure if this is a trick question. Fill jug. Weigh (m1). Drop ball in water. Weigh again(m2). Remove ball. weigh again (m3).

M1-M3 = mass of water displaced. Md
M2-M3 = mass of ball. Mb

Density of ball = Mb/Md. (g/cc, assuming pure water at STP).
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  #1808  
Old 16.04.2018, 19:54
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Re: Ask a Scientist

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Not sure if this is a trick question. Fill jug. Weigh (m1). Drop ball in water. Weigh again(m2). Remove ball. weigh again (m3).

M1-M3 = mass of water displaced. Md
M2-M3 = mass of ball. Mb

Density of ball = Mb/Md. (g/cc, assuming pure water at STP).
If you had scales, wouldn't you just weight the ball directly?
And use the jug+water to measure the increase in volume?

This gives you the 2 inputs into density, mass/volume
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